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LemonmathSelf-study sheet
Grade 12 · Lesson 6.1

Conditional probability

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Goals

Remember

Exercises

Exercise 1

A fair die is rolled. Given that the result is odd, find the probability that it is at most 33.

Exercise 2

A class has 4040 students: 2020 boys, 1414 of whom like maths, and 2020 girls, 1010 of whom like maths. One student is chosen at random. Find the probability that the student likes maths given that she is a girl, and the probability that the student is a boy given that the student likes maths.

Exercise 3

Given P(A)=0.5P(A)=0.5, P(B)=0.4P(B)=0.4 and P(A∩B)=0.2P(A\cap B)=0.2, find P(A∣B)P(A\mid B) and P(B∣A)P(B\mid A), and decide whether AA and BB are independent.

Exercise 4

A box holds 44 white balls and 66 black balls. Two balls are drawn one after the other without replacement. Find the probability that both are black, and the probability that the second is white given that the first is black.

Exercise 5

A box holds 1010 cards numbered 11 to 1010. One card is drawn at random. Let AA be "the number is even" and BB be "the number is at least 77". Is each claim true or false?

a) P(B)=0.4P(B)=0.4.

b) P(A∣B)=12P(A\mid B)=\dfrac12.

c) P(B∣A)=25P(B\mid A)=\dfrac25.

d) AA and BB are not independent.

Exercise 6

Two fair dice are rolled. Given that at least one die shows a 66, find the probability that the total is at least 1010. Give your answer to 2 decimal places.

Exercise 7

In a café, 70%70\% of customers order a coffee drink, and 40%40\% of those also order a cake. Also, 35%35\% of all customers order a cake. Find the probability that a customer orders both coffee and cake, and the probability that a customer ordered coffee given that the customer ordered cake.

Exercise 8 Review

Two marksmen fire independently at a target, one shot each, hitting with probabilities 0.80.8 and 0.70.7. Given that the target is hit at least once, find the probability that both hit it. Give your answer to 2 decimal places.

Exercise 9 Review

A group has 55 boys and 44 girls. Three of them are chosen at random. Given that at least one girl is chosen, find the probability that exactly one girl is chosen.

Exercise 10 Challenge

A fair coin is tossed three times. Let AA be "the first toss is heads" and BB be "at least two tosses are heads". Find P(A∣B)P(A\mid B) and P(B∣A)P(B\mid A), and decide whether AA and BB are independent.

Mini test

15 minutes, without looking back at the lesson. Part I: circle one letter; Part II: write T or F for each statement; Part III: write the answer in the box.

Part I. Multiple choice

Question 1. Given P(A)=0.6P(A)=0.6, P(B)=0.5P(B)=0.5 and P(A∩B)=0.2P(A\cap B)=0.2, the value of P(A∣B)P(A\mid B) is
A. 0.30.3.B. 0.40.4.C. 13\dfrac13.D. 0.10.1.
Question 2. A fair die is rolled. Given that the result is even, the probability that it is a 66 is
A. 16\dfrac16.B. 12\dfrac12.C. 13\dfrac13.D. 112\dfrac1{12}.
Question 3. A box holds 33 red and 22 blue balls. Two balls are drawn one after the other without replacement. The probability that both are red is
A. 925\dfrac{9}{25}.B. 310\dfrac{3}{10}.C. 35\dfrac35.D. 12\dfrac12.
Question 4. Of 100100 people asked, 4040 use app X and 3030 of those are satisfied; 6060 do not use X and 3030 of those are satisfied. A satisfied person is chosen at random. The probability that this person uses app X is
A. 34\dfrac34.B. 310\dfrac{3}{10}.C. 12\dfrac12.D. 35\dfrac35.

Part II. True or false

Question 1. AA and BB are independent events with P(A)=0.4P(A)=0.4 and P(B)=0.5P(B)=0.5.
a) P(A∩B)=0.2P(A\cap B)=0.2.T / F
b) P(A∣B)=0.4P(A\mid B)=0.4.T / F
c) P(A‾∣B)=0.4P(\overline{A}\mid B)=0.4.T / F
d) P(A∪B)=0.7P(A\cup B)=0.7. T / F

Part III. Short answer

Question 1. Two fair dice are rolled. Given that the total is 77, find the probability that one die shows a 11. Give your answer to 2 decimal places.
Question 2. Of 500500 people tested, 2020 have a disease and 1818 of them test positive; 480480 do not have it and 2424 of them test positive. A person who tests positive is chosen at random. Find the probability that this person has the disease. Give your answer to 2 decimal places.

Score: ........ / 10

Hints (only when stuck)

Exercise 1.

What you need: P(A∣B)=n(A∩B)n(B)P(A\mid B)=\dfrac{n(A\cap B)}{n(B)} when outcomes are equally likely.

Steps:

  1. List B={1,3,5}B=\{1, 3, 5\}.
  2. Count the elements of BB that are at most 33.
Exercise 2.

What you need: make a two-way table; read only the row (or column) of the condition.

Steps:

  1. The number who like maths is 14+10=2414+10=24.
  2. Compute 1020\dfrac{10}{20} and 1424\dfrac{14}{24}.
Exercise 3.

What you need: the definition of conditional probability; independence means P(A∣B)=P(A)P(A\mid B)=P(A).

Steps:

  1. Divide P(A∩B)P(A\cap B) by P(B)P(B), then by P(A)P(A).
  2. Compare P(A∣B)P(A\mid B) with P(A)P(A).
Exercise 4.

What you need: the multiplication rule P(A∩B)=P(A)⋅P(B∣A)P(A\cap B)=P(A)\cdot P(B\mid A); after the first draw, 99 balls remain.

Steps:

  1. P(black first)=610P(\text{black first})=\dfrac{6}{10} and P(black second∣black first)=59P(\text{black second}\mid\text{black first})=\dfrac59.
  2. If the first is black, 44 white remain out of 99.
Exercise 5.

What you need: P(A∣B)=n(A∩B)n(B)P(A\mid B)=\dfrac{n(A\cap B)}{n(B)}; independence means P(A∣B)=P(A)P(A\mid B)=P(A).

Steps:

  1. List B={7,8,9,10}B=\{7, 8, 9, 10\} and A∩B={8,10}A\cap B=\{8, 10\}.
  2. Compare P(A∣B)P(A\mid B) with P(A)=12P(A)=\dfrac12.
Exercise 6.

What you need: counting in the shrunken sample space.

Steps:

  1. Count the outcomes with at least one 66: 36−25=1136-25=11.
  2. Among them, count those with total ≥10\ge10.
Exercise 7.

What you need: "40%40\% of those" is the conditional probability P(cake∣coffee)=0.4P(\text{cake}\mid\text{coffee})=0.4.

Steps:

  1. Use the multiplication rule.
  2. Divide by P(cake)=0.35P(\text{cake})=0.35.
Exercise 8.

What you need: the multiplication rule for independent events (grade 11) and the complementary event: P(at least one)=1−P(nobody hits)P(\text{at least one})=1-P(\text{nobody hits}).

Steps:

  1. P(both hit)=0.8⋅0.7P(\text{both hit})=0.8\cdot0.7.
  2. P(at least one hit)=1−0.2⋅0.3P(\text{at least one hit})=1-0.2\cdot0.3; "both hit" lies inside "at least one hit".
Exercise 9.

What you need: counting with combinations (see permutations, arrangements and combinations).

Steps:

  1. The number of choices with at least one girl is (93)−(53)\binom{9}{3}-\binom{5}{3}.
  2. The number with exactly one girl is (41)⋅(52)\binom{4}{1}\cdot\binom{5}{2}.
Exercise 10.

What you need: list the 88 equally likely outcomes; independence means P(A∣B)=P(A)P(A\mid B)=P(A).

Steps:

  1. Write BB (H for heads, T for tails): HHT, HTH, THH, HHH.
  2. Count A∩BA\cap B, then divide by n(B)n(B) and by n(A)=4n(A)=4.

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