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LemonmathSelf-study sheet
Grade 12 · Lesson 1.1

Monotonicity and extrema

Name: Date: Time spent: min

Goals

Remember

Exercises

Exercise 1

Find the intervals on which y=−x3+3x2+1y=-x^3+3x^2+1 is increasing or decreasing.

Exercise 2

Find the extrema of y=x4−8x2+1y=x^4-8x^2+1.

Exercise 3

Determine where y=x+2x−1y=\dfrac{x+2}{x-1} is increasing or decreasing.

Exercise 4

Find the extrema of y=x+4xy=x+\dfrac{4}{x}.

Exercise 5

A function y=f(x)y=f(x) has derivative f′(x)=x(x−1)2(x+2)f'(x)=x(x-1)^2(x+2) for every x∈Rx\in\mathbb{R}. Is each claim true or false?

a) ff is increasing on the interval (0,+∞)(0, +\infty).

b) ff has three turning points.

c) ff has a local maximum at x=−2x=-2.

d) ff is decreasing on the interval (−2,1)(-2, 1).

Exercise 6

The function y=x3−3x2−9x+4y=x^3-3x^2-9x+4 has a local maximum value ymaxy_{\text{max}} and a local minimum value yminy_{\text{min}}. Compute ymax−yminy_{\text{max}}-y_{\text{min}}.

Exercise 7

The concentration of a medicine in the blood tt hours after an injection is C(t)=30tt2+9C(t)=\dfrac{30t}{t^2+9} (mg/l), t>0t>0. During which time interval does the concentration increase, and when does it decrease? When does it reach its local maximum, and what is that value?

Exercise 8 Review

Find the extrema of y=x+2cos⁡xy=x+2\cos x on the interval (0,π)(0, \pi).

Exercise 9 Review

Prove that y=x3+x2+x+1y=x^3+x^2+x+1 is increasing on R\mathbb{R}.

Exercise 10 Challenge

Find the intervals on which y=x4−x2y=x\sqrt{4-x^2} is increasing or decreasing, and its extrema.

Mini test

15 minutes, without looking back at the lesson. Part I: circle one letter; Part II: write T or F for each statement; Part III: write the answer in the box.

Part I. Multiple choice

Question 1. On which of these intervals is y=x3−3x2+2y=x^3-3x^2+2 decreasing?
A. (−∞,0)(-\infty, 0).B. (2,+∞)(2, +\infty).C. (0,2)(0, 2).D. (−2,0)(-2, 0).
Question 2. The function y=−x3+3x+1y=-x^3+3x+1 has a local maximum at
A. x=−1x=-1.B. x=1x=1.C. x=3x=3.D. x=0x=0.
Question 3. A function y=f(x)y=f(x) has a second derivative on R\mathbb{R}, with f′(2)=0f'(2)=0 and f′′(2)=−3f''(2)=-3. Which statement is correct?
A. ff has a local minimum at x=2x=2.B. ff has a local maximum at x=−3x=-3.C. ff has no extremum at x=2x=2.D. ff has a local maximum at x=2x=2.
Question 4. Which function is increasing on R\mathbb{R}?
A. y=x3+3x−1y=x^3+3x-1.B. y=x3−3xy=x^3-3x.C. y=2x+1x+3y=\dfrac{2x+1}{x+3}.D. y=x4+2x2y=x^4+2x^2.

Part II. True or false

Question 1. Let f(x)=2x3−3x2−12x+1f(x)=2x^3-3x^2-12x+1.
a) f′(x)=6x2−6x−12f'(x)=6x^2-6x-12.T / F
b) ff is increasing on the interval (−1,2)(-1, 2).T / F
c) The local maximum value of ff is 88.T / F
d) The line through the two turning points of the graph has gradient 99. T / F

Part III. Short answer

Question 1. Find the sum of the local maximum value and the local minimum value of y=−x4+8x2−3y=-x^4+8x^2-3.
Question 2. The water level in a reservoir after tt hours is modelled by h(t)=t3−15t2+60t+100h(t)=t^3-15t^2+60t+100 (cm), 0≤t≤120\le t\le 12. For how many hours does the water level fall? Give your answer to 1 decimal place.

Score: ........ / 10

Hints (only when stuck)

Exercise 1.

What you need: if y′>0y'>0 on an interval, the function is increasing there; if y′<0y'<0, it is decreasing.

Steps:

  1. Compute y′y' and factorise it.
  2. Find the sign of y′y' (mind the negative coefficient).
Exercise 2.

What you need: y′y' changes sign from −- to ++ at a local minimum and from ++ to −- at a local maximum.

Steps:

  1. Compute y′=4x3−16xy'=4x^3-16x and find its three roots.
  2. Draw the table of variations.
  3. Compute yy at these points.
Exercise 3.

What you need: (ax+bcx+d)′=ad−bc(cx+d)2\left(\dfrac{ax+b}{cx+d}\right)'=\dfrac{ad-bc}{(cx+d)^2}.

Steps:

  1. Find the domain.
  2. Compute y′y' and look at the sign of the numerator.
Exercise 4.

What you need: write y′y' as one fraction to find its sign; remember x=0x=0 is not in the domain.

Steps:

  1. Compute y′=1−4x2=x2−4x2y'=1-\dfrac{4}{x^2}=\dfrac{x^2-4}{x^2}.
  2. Draw the table of variations with the values −2-2, 00, 22 marked.
Exercise 5.

What you need: the factor (x−1)2(x-1)^2 is non-negative, so it does not make f′f' change sign; extrema occur only where f′f' changes sign.

Steps:

  1. Make a sign table of f′f' with the values −2-2, 00, 11 marked.
  2. Read off where ff increases or decreases and where f′f' changes sign.
Exercise 6.

What you need: for a cubic with two extrema and a>0a>0, the local maximum occurs at the smaller root of y′y'.

Steps:

  1. Solve y′=3x2−6x−9=0y'=3x^2-6x-9=0.
  2. Compute yy at the two roots.
Exercise 7.

What you need: the quotient rule (uv)′=u′v−uv′v2\left(\dfrac{u}{v}\right)'=\dfrac{u'v-uv'}{v^2}.

Steps:

  1. Compute C′(t)C'(t) and simplify the numerator.
  2. Find the sign of C′(t)C'(t) for t>0t>0.
Exercise 8.

What you need: the equation sin⁡x=12\sin x=\dfrac12 (basic trigonometric equations, grade 11) and the second-derivative test.

Steps:

  1. Solve y′=1−2sin⁡x=0y'=1-2\sin x=0 on (0,π)(0, \pi).
  2. Compute y′′=−2cos⁡xy''=-2\cos x at each root.
Exercise 9.

What you need: a quadratic expression with Δ<0\Delta<0 always has the sign of aa (see the sign of a quadratic expression).

Steps:

  1. Compute y′y'.
  2. Compute the discriminant of y′y' and look at the sign of aa.
Exercise 10.

What you need: (u)′=u′2u\left(\sqrt{u}\right)'=\dfrac{u'}{2\sqrt{u}}; a square root is defined only when the expression under it is non-negative.

Steps:

  1. Find the domain.
  2. Compute y′y' and write it as a single fraction.
  3. Find the sign of the numerator on (−2,2)(-2, 2).

Self-check

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