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LemonmathSelf-study sheet
Grade 12 · Lesson 7.4

Revision: antiderivatives and integrals

Name: Date: Time spent: min

Goals

Exercises

Exercise 1 Multiple choice

∫(4x3−1x2)dx\displaystyle\int\left(4x^3-\frac{1}{x^2}\right)dx equals A. x4+1x+Cx^4+\dfrac1x+C. B. x4−1x+Cx^4-\dfrac1x+C. C. 12x2+2x3+C12x^2+\dfrac{2}{x^3}+C. D. x4+13x3+Cx^4+\dfrac{1}{3x^3}+C.

Exercise 2 Multiple choice

∫0π2cos⁡x dx\displaystyle\int_0^{\frac{\pi}{2}}\cos x\,dx equals A. 11. B. 00. C. −1-1. D. π2\dfrac{\pi}{2}.

Exercise 3 Short answer

Evaluate ∫02(3x2−2x+1)dx\displaystyle\int_0^2\left(3x^2-2x+1\right)dx.

Exercise 4 True/False

Let f(x)=ex+2xf(x)=e^x+2x.

a) F(x)=ex+x2F(x)=e^x+x^2 is an antiderivative of f(x)f(x).

b) ∫01f(x) dx=e+1\displaystyle\int_0^1 f(x)\,dx=e+1.

c) The antiderivative FF of ff with F(0)=3F(0)=3 is F(x)=ex+x2+3F(x)=e^x+x^2+3.

d) ∫−11f(x) dx=e−1e\displaystyle\int_{-1}^1 f(x)\,dx=e-\dfrac1e.

Exercise 5 Short answer

Find the area of the region bounded by the parabola y=x2−4y=x^2-4 and the xx-axis. Give your answer to 1 decimal place.

Exercise 6 Written answer

Find the area of the region bounded by the graph of y=x3−xy=x^3-x, the xx-axis and the lines x=0x=0, x=2x=2.

Exercise 7 Multiple choice

Rotating the region bounded by y=2xy=2x, the xx-axis and the line x=3x=3 about the xx-axis gives a cone of volume A. 36π36\pi. B. 9π9\pi. C. 108π108\pi. D. 18π18\pi.

Exercise 8 Short answer

Water flows into a tank at a rate of r(t)=0.6t+2r(t)=0.6t+2 (litres per minute), with tt in minutes. How many litres flow into the tank in the first 1010 minutes?

Exercise 9 True/False

A car brakes and slows down uniformly with velocity v(t)=12−3tv(t)=12-3t (m/s), where tt is the time in seconds since braking.

a) The car stops after 44 seconds.

b) The distance travelled tt seconds after braking is s(t)=12t−1.5t2s(t)=12t-1.5t^2 (m), 0≤t≤40\le t\le4.

c) From braking to stopping, the car travels 2424 m.

d) In the last second before stopping, the car travels 33 m.

Exercise 10 Challenge

A gateway has the shape of a parabola: it is 88 m wide at ground level and its top is 44 m above the ground. The whole gateway is filled with glass. Find the area of glass, in m², to 1 decimal place.

Mini test

15 minutes, without looking back at the lesson. Part I: circle one letter; Part II: write T or F for each statement; Part III: write the answer in the box.

Part I. Multiple choice

Question 1. The family of antiderivatives of f(x)=2xf(x)=2^x is
A. 2xln⁡2+C\dfrac{2^x}{\ln2}+C.B. 2xln⁡2+C2^x\ln2+C.C. 2x+1x+1+C\dfrac{2^{x+1}}{x+1}+C.D. x⋅2x−1+Cx\cdot2^{x-1}+C.
Question 2. ∫121x dx\displaystyle\int_1^2\frac1x\,dx equals
A. ln⁡2\ln2.B. 34\dfrac34.C. ln⁡3\ln3.D. 12\dfrac12.
Question 3. The functions ff, gg are continuous on [a,b][a, b]. The area of the region bounded by y=f(x)y=f(x), y=g(x)y=g(x), x=ax=a, x=bx=b is
A. ∫ab∣f(x)−g(x)∣ dx\displaystyle\int_a^b\lvert f(x)-g(x)\rvert\,dx.B. ∫ab[f(x)−g(x)]dx\displaystyle\int_a^b\left[f(x)-g(x)\right]dx.C. π∫ab[f(x)−g(x)]2dx\pi\displaystyle\int_a^b\left[f(x)-g(x)\right]^2dx.D. ∣∫ab[f(x)−g(x)]dx∣\left\lvert\displaystyle\int_a^b\left[f(x)-g(x)\right]dx\right\rvert.
Question 4. Given ∫02f(x) dx=3\displaystyle\int_0^2 f(x)\,dx=3, the value of ∫02[2f(x)+x]dx\displaystyle\int_0^2\left[2f(x)+x\right]dx is
A. 88.B. 77.C. 66.D. 1010.

Part II. True or false

Question 1. The region HH is bounded by y=x2y=x^2, the xx-axis and the lines x=0x=0, x=3x=3.
a) The area of HH is S=∫03x2 dxS=\displaystyle\int_0^3x^2\,dx.T / F
b) S=9S=9.T / F
c) The volume of the solid formed by rotating HH about the xx-axis is V=π∫03x2 dxV=\pi\displaystyle\int_0^3x^2\,dx.T / F
d) V=243π5V=\dfrac{243\pi}{5}. T / F

Part III. Short answer

Question 1. An object moves with velocity v(t)=3t2+2tv(t)=3t^2+2t (m/s). Find the distance it travels from t=0t=0 to t=4t=4 seconds, in metres.
Question 2. Evaluate ∫01(ex+1)dx\displaystyle\int_0^1\left(e^x+1\right)dx. Give your answer to 2 decimal places.

Score: ........ / 10

Hints (only when stuck)

Exercise 1.

What you need: 1x2=x−2\dfrac{1}{x^2}=x^{-2} and ∫xα dx=xα+1α+1+C\displaystyle\int x^{\alpha}\,dx=\dfrac{x^{\alpha+1}}{\alpha+1}+C.

Steps:

  1. ∫x−2 dx=x−1−1=−1x\displaystyle\int x^{-2}\,dx=\dfrac{x^{-1}}{-1}=-\dfrac1x.
  2. Watch the minus sign in front.
Exercise 2.

What you need: an antiderivative of cos⁡x\cos x is sin⁡x\sin x.

Steps:

  1. Work out sin⁡π2−sin⁡0\sin\dfrac{\pi}{2}-\sin0.
Exercise 3.

What you need: the Newton–Leibniz formula.

Steps:

  1. An antiderivative is x3−x2+xx^3-x^2+x.
  2. Substitute the limits 22 and 00.
Exercise 4.

What you need: check an antiderivative by differentiating; e0=1e^0=1.

Steps:

  1. Write F(x)=ex+x2+CF(x)=e^x+x^2+C.
  2. Evaluate each integral with [ex+x2]\Big[e^x+x^2\Big].
Exercise 5.

What you need: S=∫ab∣f(x)∣ dxS=\displaystyle\int_a^b\lvert f(x)\rvert\,dx, where aa, bb are the intersections with the xx-axis.

Steps:

  1. Solve x2−4=0x^2-4=0.
  2. On [−2,2][-2, 2], x2−4≤0x^2-4\le0, so ∣x2−4∣=4−x2\lvert x^2-4\rvert=4-x^2.
Exercise 6.

What you need: split the interval at the roots of f(x)f(x) to remove the modulus.

Steps:

  1. x3−x=x(x−1)(x+1)x^3-x=x(x-1)(x+1): negative on (0,1)(0, 1), positive on (1,2)(1, 2).
  2. Evaluate the two integrals and add.
Exercise 7.

What you need: V=π∫abf2(x) dxV=\pi\displaystyle\int_a^b f^2(x)\,dx, here with f2(x)=4x2f^2(x)=4x^2.

Steps:

  1. Work out π∫034x2 dx\pi\displaystyle\int_0^3 4x^2\,dx.
  2. Check with the cone formula 13πr2h\dfrac13\pi r^2h.
Exercise 8.

What you need: the amount of water is ∫010r(t) dt\displaystyle\int_0^{10} r(t)\,dt.

Steps:

  1. An antiderivative is 0.3t2+2t0.3t^2+2t.
  2. Substitute the limits.
Exercise 9.

What you need: s(t)=∫0tv(u) dus(t)=\displaystyle\int_0^t v(u)\,du; the distance from t=at=a to t=bt=b is s(b)−s(a)s(b)-s(a).

Steps:

  1. Solve v(t)=0v(t)=0.
  2. Work out s(4)s(4) and s(4)−s(3)s(4)-s(3).
Exercise 10.

What you need: put the origin at the middle of the base with the yy-axis through the top; the area is ∫−44f(x) dx\displaystyle\int_{-4}^4 f(x)\,dx.

Steps:

  1. The parabola passes through (−4,0)(-4, 0), (4,0)(4, 0), (0,4)(0, 4): y=4−x24y=4-\dfrac{x^2}{4}.
  2. Evaluate the integral.

Self-check

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