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LemonmathSelf-study sheet
Grade 12 · Lesson 4.2

Definite integrals

Name: Date: Time spent: min

Goals

Remember

Exercises

Exercise 1

Evaluate ∫02(x3−2x+3) dx\displaystyle\int_0^2(x^3-2x+3)\,dx.

Exercise 2

Evaluate ∫14(x−1x2)dx\displaystyle\int_1^4\left(\sqrt x-\frac{1}{x^2}\right)dx.

Exercise 3

Evaluate ∫0π(sin⁡x+2) dx\displaystyle\int_0^{\pi}(\sin x+2)\,dx.

Exercise 4

Given ∫13f(x) dx=5\displaystyle\int_1^3 f(x)\,dx=5 and ∫13g(x) dx=−2\displaystyle\int_1^3 g(x)\,dx=-2, find ∫13(3f(x)−2g(x)+x) dx\displaystyle\int_1^3\big(3f(x)-2g(x)+x\big)\,dx.

Exercise 5

Consider the integral I=∫03∣x−2∣ dxI=\displaystyle\int_0^3\lvert x-2\rvert\,dx. Is each claim true or false?

a) On [0,2][0, 2], ∣x−2∣=2−x\lvert x-2\rvert=2-x.

b) I=∣∫03(x−2) dx∣=32I=\left\lvert\displaystyle\int_0^3(x-2)\,dx\right\rvert=\dfrac32.

c) I=52I=\dfrac52.

d) ∫30∣x−2∣ dx=52\displaystyle\int_3^0\lvert x-2\rvert\,dx=\dfrac52.

Exercise 6

Evaluate ∫01(3x+1)2 dx\displaystyle\int_0^1(3x+1)^2\,dx.

Exercise 7

Water flows into a tank at the rate r(t)=40−2tr(t)=40-2t (litres per minute), 0≤t≤100\le t\le10. How much water flows into the tank in the first 1010 minutes?

Exercise 8 Review

F(x)F(x) is an antiderivative of f(x)f(x) on R\mathbb{R} with F(1)=2F(1)=2 and F(4)=7F(4)=7. Find ∫14f(x) dx\displaystyle\int_1^4 f(x)\,dx and ∫14(2f(x)+1) dx\displaystyle\int_1^4\big(2f(x)+1\big)\,dx.

Exercise 9 Review

Evaluate ∫0ln⁡3ex dx\displaystyle\int_0^{\ln3}e^x\,dx and ∫122x dx\displaystyle\int_1^2 2^x\,dx (give the second one to 2 decimal places).

Exercise 10 Challenge

Evaluate ∫−12∣x2−x∣ dx\displaystyle\int_{-1}^2\lvert x^2-x\rvert\,dx.

Mini test

15 minutes, without looking back at the lesson. Part I: circle one letter; Part II: write T or F for each statement; Part III: write the answer in the box.

Part I. Multiple choice

Question 1. The integral ∫12(2x+1) dx\displaystyle\int_1^2(2x+1)\,dx equals
A. 66.B. −4-4.C. 44.D. 22.
Question 2. Given ∫05f(x) dx=7\displaystyle\int_0^5 f(x)\,dx=7 and ∫02f(x) dx=3\displaystyle\int_0^2 f(x)\,dx=3, the value of ∫25f(x) dx\displaystyle\int_2^5 f(x)\,dx is
A. 1010.B. 44.C. −4-4.D. −10-10.
Question 3. The integral ∫0πsin⁡x dx\displaystyle\int_0^{\pi}\sin x\,dx equals
A. −2-2.B. 11.C. 22.D. 00.
Question 4. The integral ∫01e2x dx\displaystyle\int_0^1 e^{2x}\,dx equals
A. e2−1e^2-1.B. e2−12\dfrac{e^2-1}{2}.C. 2(e2−1)2(e^2-1).D. e22\dfrac{e^2}{2}.

Part II. True or false

Question 1. Consider f(x)=x2−4x+3f(x)=x^2-4x+3.
a) ∫03f(x) dx=0\displaystyle\int_0^3 f(x)\,dx=0.T / F
b) f(x)≤0f(x)\le0 for every x∈[1,3]x\in[1, 3].T / F
c) ∫03∣f(x)∣ dx=0\displaystyle\int_0^3\lvert f(x)\rvert\,dx=0.T / F
d) ∫03∣f(x)∣ dx=83\displaystyle\int_0^3\lvert f(x)\rvert\,dx=\dfrac83. T / F

Part III. Short answer

Question 1. Evaluate ∫02(x3+3x2) dx\displaystyle\int_0^2(x^3+3x^2)\,dx.
Question 2. Evaluate ∫1e(2x+1x)dx\displaystyle\int_1^e\left(2x+\frac1x\right)dx. Give your answer to 1 decimal place.

Score: ........ / 10

Hints (only when stuck)

Exercise 1.

What you need: ∫abf(x) dx=F(b)−F(a)\displaystyle\int_a^b f(x)\,dx=F(b)-F(a).

Steps:

  1. Find an antiderivative F(x)=x44−x2+3xF(x)=\dfrac{x^4}{4}-x^2+3x.
  2. Compute F(2)−F(0)F(2)-F(0).
Exercise 2.

What you need: x=x12\sqrt x=x^{\frac12} has antiderivative 23xx\dfrac23x\sqrt x; x−2x^{-2} has antiderivative −1x-\dfrac1x.

Steps:

  1. Write an antiderivative F(x)=23xx+1xF(x)=\dfrac23x\sqrt x+\dfrac1x.
  2. Compute F(4)−F(1)F(4)-F(1), taking care with the fractions.
Exercise 3.

What you need: the antiderivative of sin⁡x\sin x is −cos⁡x-\cos x; cos⁡π=−1\cos\pi=-1 and cos⁡0=1\cos0=1.

Steps:

  1. Write F(x)=−cos⁡x+2xF(x)=-\cos x+2x.
  2. Compute F(π)−F(0)F(\pi)-F(0).
Exercise 4.

What you need: split the sum and take constants outside the integral.

Steps:

  1. Write it as 3⋅5−2⋅(−2)+∫13x dx3\cdot5-2\cdot(-2)+\displaystyle\int_1^3x\,dx.
  2. Evaluate ∫13x dx\displaystyle\int_1^3x\,dx.
Exercise 5.

What you need: split the interval where x−2x-2 changes sign; swapping the limits changes the sign.

Steps:

  1. Find the sign of x−2x-2 on [0,2][0, 2] and on [2,3][2, 3].
  2. Evaluate the two smaller integrals and add.
Exercise 6.

What you need: ∫f(ax+b) dx=1aF(ax+b)+C\displaystyle\int f(ax+b)\,dx=\frac1aF(ax+b)+C, here with a=3a=3.

Steps:

  1. An antiderivative is (3x+1)39\dfrac{(3x+1)^3}{9}.
  2. Substitute the limits 11 and 00.
Exercise 7.

What you need: the amount that flows in from t=at=a to t=bt=b is ∫abr(t) dt\displaystyle\int_a^b r(t)\,dt (the rate is non-negative).

Steps:

  1. Write ∫010(40−2t) dt\displaystyle\int_0^{10}(40-2t)\,dt.
  2. Evaluate it with the antiderivative 40t−t240t-t^2.
Exercise 8.

What you need: the definition of the integral through an antiderivative (see antiderivatives).

Steps:

  1. ∫14f(x) dx=F(4)−F(1)\displaystyle\int_1^4f(x)\,dx=F(4)-F(1).
  2. Split the sum; ∫141 dx=3\displaystyle\int_1^41\,dx=3.
Exercise 9.

What you need: eln⁡a=ae^{\ln a}=a (logarithms, grade 11); the antiderivative of 2x2^x is 2xln⁡2\dfrac{2^x}{\ln2}.

Steps:

  1. [ex]0ln⁡3=eln⁡3−e0\Big[e^x\Big]_0^{\ln3}=e^{\ln3}-e^0.
  2. [2xln⁡2]12=4−2ln⁡2\Big[\dfrac{2^x}{\ln2}\Big]_1^2=\dfrac{4-2}{\ln2}.
Exercise 10.

What you need: x2−x=x(x−1)x^2-x=x(x-1) changes sign at 00 and 11; it is positive outside the roots and negative between them.

Steps:

  1. Split into the three intervals [−1,0][-1, 0], [0,1][0, 1], [1,2][1, 2].
  2. Use the antiderivative G(x)=x33−x22G(x)=\dfrac{x^3}{3}-\dfrac{x^2}{2} on each piece, changing the sign on the middle one.

Self-check

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