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LemonmathSelf-study sheet
Grade 9 · Lesson 6.2

Quadratic equations in one unknown

Name: Date: Time spent: min

Goals

Remember

Exercises

Exercise 1

Solve the following equations:

a) 5x2−20=05x^2-20=0.

b) −2x2+6x=0-2x^2+6x=0.

Exercise 2

Solve the following equations using the quadratic formula:

a) x2−7x+10=0x^2-7x+10=0.

b) 2x2+x−1=02x^2+x-1=0.

c) 9x2−6x+1=09x^2-6x+1=0.

Exercise 3

Solve the following equations using the reduced discriminant:

a) x2−4x−1=0x^2-4x-1=0.

b) 5x2+2x+1=05x^2+2x+1=0.

Exercise 4

Solve the following equations:

a) (x+1)(x−3)=2x−7(x+1)(x-3)=2x-7.

b) x(x+2)=3(x+4)x(x+2)=3(x+4).

Exercise 5

Suppose a ball is kicked straight up from the ground and its height after tt seconds is h=−5t2+20th=-5t^2+20t (metres). After how many seconds is the ball at a height of 1515 m?

Exercise 6

Suppose Mrs Lan puts 100100 million dong into a savings account at an interest rate rr per year, and the first year's interest is added to the capital before the second year's interest is worked out (compound interest). After 22 years she receives 112.36112.36 million dong. Find the interest rate rr.

Exercise 7

Solve the equation xx−2−1x=2x(x−2)\dfrac{x}{x-2}-\dfrac1x=\dfrac{2}{x(x-2)}. (Revise equations with the unknown in a denominator.)

Exercise 8

(2.0 marks)

a) Solve the equation 2x2−3x−5=02x^2-3x-5=0.

b) Find the coordinates of the points where the parabola (P):y=x2(P): y=x^2 meets the line (d):y=x+2(d): y=x+2.

c) Solve the equation x2−22x−6=0x^2-2\sqrt2x-6=0.

Exercise 9 Challenge

From a rectangular metal sheet 3030 cm long and 2020 cm wide, four equal squares are cut from the corners and the sides are folded up to make an open box. How long must the side of each square be for the base of the box to have area 336336 cm²? What is the volume of the box then, in cubic centimetres?

Mini test

15 minutes, without looking back at the lesson. Part I: circle one letter; Part II: write T or F for each statement; Part III: write the answer in the box.

Part I. Multiple choice

Question 1. Which of the following is a quadratic equation in one unknown?
A. 2x+3=02x+3=0.B. x3−x=0x^3-x=0.C. −x2+5=0-x^2+5=0.D. 0x2+3x−1=00x^2+3x-1=0.
Question 2. The discriminant Δ\Delta of the equation 2x2−3x−2=02x^2-3x-2=0 is
A. 2525.B. −7-7.C. 1717.D. 77.
Question 3. The equation x2−6x+9=0x^2-6x+9=0
A. has two distinct roots 33 and −3-3.B. has a repeated root x=3x=3.C. has a repeated root x=−3x=-3.D. has no solutions.
Question 4. The reduced discriminant Δ′\Delta' of the equation 3x2−4x−1=03x^2-4x-1=0 is
A. 77.B. 11.C. 2828.D. 1919.

Part II. True or false

Question 1. Consider the equation x2−2x−8=0x^2-2x-8=0. Decide whether each statement is true or false.
a) The coefficients are a=1a=1, b=−2b=-2, c=−8c=-8.T / F
b) Δ′=9\Delta'=9.T / F
c) The equation has the two roots x=−4x=-4 and x=2x=2.T / F
d) The equation has a repeated root. T / F

Part III. Short answer

Question 1. Find the positive root of the equation x2+x−12=0x^2+x-12=0.
Question 2. Find the smaller root of the equation 2x2−5x−3=02x^2-5x-3=0 (give your answer as a decimal).

Score: ........ / 10

Hints (only when stuck)

Exercise 1.

What you need: if b=0b=0, rewrite as x2=kx^2=k; if c=0c=0, take out a common factor.

Steps:

  1. a) Rearrange and divide by 55.
  2. b) Write −2x(x−3)=0-2x(x-3)=0.
Exercise 2.

What you need: Δ=b2−4ac\Delta=b^2-4ac and the quadratic formula.

Steps:

  1. Identify aa, bb, cc and work out Δ\Delta.
  2. Look at the sign of Δ\Delta, then apply the formula.
Exercise 3.

What you need: b=2b′b=2b', Δ′=b′2−ac\Delta'=b'^2-ac.

Steps:

  1. Find b′b' and work out Δ′\Delta'.
  2. Apply x1,2=−b′±Δ′ax_{1,2}=\dfrac{-b'\pm\sqrt{\Delta'}}{a}.
Exercise 4.

What you need: expand and rearrange into the form ax2+bx+c=0ax^2+bx+c=0.

Steps:

  1. Expand both sides and move everything to the left-hand side.
  2. Solve the resulting quadratic equation.
Exercise 5.

What you need: solve the equation −5t2+20t=15-5t^2+20t=15 with t≥0t\geq0.

Steps:

  1. Rearrange and divide both sides by −5-5.
  2. Solve the resulting equation, then explain what the two roots mean.
Exercise 6.

What you need: each year the amount is multiplied by 1+r1+r.

Steps:

  1. Form the equation 100(1+r)2=112.36100(1+r)^2=112.36.
  2. Solve it as X2=kX^2=k with X=1+r>0X=1+r>0.
Exercise 7.

What you need: find the conditions for the equation to be defined, clear the denominators and check the conditions.

Steps:

  1. Conditions: x≠0x\neq0, x≠2x\neq2.
  2. Multiply both sides by x(x−2)x(x-2).
  3. Solve the resulting quadratic equation and reject any root that breaks the conditions.
Exercise 8.

What you need: the quadratic formula; the xx-coordinates of the points where (P)(P) meets (d)(d) are the roots of x2=x+2x^2=x+2.

Steps:

  1. a) Work out Δ\Delta.
  2. b) Solve x2−x−2=0x^2-x-2=0, then work out y=x2y=x^2.
  3. c) Use b′=−2b'=-\sqrt2.
Exercise 9.

What you need: the base of the box is a rectangle (30−2x)×(20−2x)(30-2x)\times(20-2x), and the height of the box is xx.

Steps:

  1. Let the side of the square be xx (cm), 0<x<100<x<10.
  2. Form and solve the equation (30−2x)(20−2x)=336(30-2x)(20-2x)=336.
  3. Check against the condition, then find the volume.

Self-check

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