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Grade 12 · Lesson 7.6

Revision: coordinates in space

Name: Date: Time spent: min

Goals

Exercises

Exercise 1 Multiple choice

The plane through M(1,−2,3)M(1, -2, 3) with normal vector n⃗=(2,−1,1)\vec n=(2, -1, 1) has equation

A. 2x−y+z−7=02x-y+z-7=0. B. 2x−y+z+7=02x-y+z+7=0. C. x−2y+3z−7=0x-2y+3z-7=0. D. 2x−y+z−3=02x-y+z-3=0.

Exercise 2 Multiple choice

The distance from M(1,2,3)M(1, 2, 3) to the plane (P) ⁣:2x−2y+z+3=0(P)\colon 2x-2y+z+3=0 is

A. 44. B. 49\dfrac49. C. 43\dfrac43. D. 23\dfrac23.

Exercise 3 Multiple choice

The sphere (S) ⁣:x2+y2+z2−2x+4y−6z−2=0(S)\colon x^2+y^2+z^2-2x+4y-6z-2=0 has centre II and radius RR given by

A. I(1,−2,3)I(1, -2, 3), R=4R=4. B. I(−1,2,−3)I(-1, 2, -3), R=4R=4. C. I(1,−2,3)I(1, -2, 3), R=23R=2\sqrt3. D. I(2,−4,6)I(2, -4, 6), R=4R=4.

Exercise 4 True/false

Consider the line d ⁣:x=1+td\colon x=1+t, y=2−ty=2-t, z=2tz=2t and the plane (P) ⁣:x+y+z−3=0(P)\colon x+y+z-3=0.

a) dd has direction vector u⃗=(1,−1,2)\vec u=(1, -1, 2).

b) The point A(2,1,2)A(2, 1, 2) lies on dd.

c) dd is parallel to (P)(P).

d) dd meets (P)(P) at the point (1,2,0)(1, 2, 0).

Exercise 5 Short answer

Find the angle between the lines d1 ⁣:x=td_1\colon x=t, y=1+ty=1+t, z=2z=2 and d2 ⁣:x=1d_2\colon x=1, y=2+sy=2+s, z=−sz=-s (in degrees).

Exercise 6 Short answer

Let A(1,0,1)A(1, 0, 1), B(2,1,0)B(2, 1, 0), C(0,2,3)C(0, 2, 3). Find the distance from the origin OO to the plane (ABC)(ABC) (to 2 decimal places).

Exercise 7 Short answer

A room is a cuboid 66 m long, 44 m wide and 33 m high. Choose axes OxyzOxyz with the origin at a corner of the floor and the axes along three edges, in metres. A straight wire is stretched from the point A(0,0,3)A(0, 0, 3) in a corner of the ceiling to the point B(6,4,0)B(6, 4, 0) in the opposite corner of the floor. Find the length of the wire (in m, to 2 decimal places).

Exercise 8 Short answer

A drone starts at the origin OO and flies in a straight line; after tt seconds it is at M(2t,2t,t)M(2t, 2t, t) (in metres). The no-fly zone is the region of space where x+2y+2z≥30x+2y+2z\ge30. After how many seconds does the drone start to enter the no-fly zone?

Exercise 9 Written answer

Let A(3,1,−2)A(3, 1, -2) and the plane (P) ⁣:x+2y−2z=0(P)\colon x+2y-2z=0. Write the equations of the line dd through AA perpendicular to (P)(P), find the orthogonal projection HH of AA on (P)(P), and find d(A,(P))d(A, (P)).

Exercise 10 Short answer (challenge)

The sphere (S)(S) has centre I(1,2,−1)I(1, 2, -1) and touches the plane (P) ⁣:2x−y+2z+11=0(P)\colon 2x-y+2z+11=0 at the point H(a,b,c)H(a, b, c). Find a+b+ca+b+c.

Mini test

15 minutes, without looking back at the lesson. Part I: circle one letter; Part II: write T or F for each statement; Part III: write the answer in the box.

Part I. Multiple choice

Question 1. In OxyzOxyz, let A(1,2,3)A(1, 2, 3) and B(3,0,4)B(3, 0, 4). The length of ABAB is
A. 99.B. 33.C. 222\sqrt2.D. 55.
Question 2. A normal vector of the plane (P) ⁣:2x−3z+1=0(P)\colon 2x-3z+1=0 is
A. (2,−3,1)(2, -3, 1).B. (2,0,−3)(2, 0, -3).C. (2,−3,0)(2, -3, 0).D. (0,2,−3)(0, 2, -3).
Question 3. The line through A(1,−1,2)A(1, -1, 2) with direction vector u⃗=(2,1,−1)\vec u=(2, 1, -1) has parametric equations
A. x=1+2tx=1+2t, y=−1+ty=-1+t, z=2−tz=2-t.B. x=2+tx=2+t, y=1−ty=1-t, z=−1+2tz=-1+2t.C. x=1+2tx=1+2t, y=1+ty=1+t, z=2−tz=2-t.D. x=−1+2tx=-1+2t, y=1+ty=1+t, z=−2−tz=-2-t.
Question 4. The angle between the planes (P) ⁣:x−z=0(P)\colon x-z=0 and (Q) ⁣:y−z=0(Q)\colon y-z=0 is
A. 30∘30^\circ.B. 45∘45^\circ.C. 60∘60^\circ.D. 90∘90^\circ.

Part II. True or false

Question 1. Consider the sphere (S) ⁣:(x−1)2+(y+2)2+z2=9(S)\colon(x-1)^2+(y+2)^2+z^2=9 and the plane (P) ⁣:2x+y−2z+3=0(P)\colon 2x+y-2z+3=0.
a) (S)(S) has centre I(1,−2,0)I(1, -2, 0).T / F
b) (S)(S) has radius 99.T / F
c) The distance from the centre II to (P)(P) is 11.T / F
d) (P)(P) cuts (S)(S) in a circle of radius 222\sqrt2. T / F

Part III. Short answer

Question 1. Find the distance between the parallel planes (P) ⁣:2x−y+2z+1=0(P)\colon 2x-y+2z+1=0 and (Q) ⁣:2x−y+2z−8=0(Q)\colon 2x-y+2z-8=0.
Question 2. In a room, choose axes OxyzOxyz (unit: m) with the origin OO at a corner of the floor. A light bulb hangs at the point L(2,3,4)L(2, 3, 4). Find the distance from the bulb to the corner OO (in m, to 2 decimal places).

Score: ........ / 10

Hints (only when stuck)

Exercise 1.

What you need: A(x−x0)+B(y−y0)+C(z−z0)=0A(x-x_0)+B(y-y_0)+C(z-z_0)=0.

Steps:

  1. Substitute n⃗\vec n and the coordinates of MM into the formula.
  2. Expand and simplify.
Exercise 2.

What you need: d(M,(P))=∣Ax0+By0+Cz0+D∣A2+B2+C2d(M, (P))=\dfrac{|Ax_0+By_0+Cz_0+D|}{\sqrt{A^2+B^2+C^2}}.

Steps:

  1. Compute the numerator ∣2−4+3+3∣|2-4+3+3|.
  2. Compute the denominator 4+4+1\sqrt{4+4+1}.
Exercise 3.

What you need: −2a=−2-2a=-2, −2b=4-2b=4, −2c=−6-2c=-6; R=a2+b2+c2−dR=\sqrt{a^2+b^2+c^2-d}.

Steps:

  1. Find aa, bb, cc.
  2. Compute RR with d=−2d=-2.
Exercise 4.

What you need: if d∥(P)d\parallel(P) then u⃗⋅n⃗=0\vec u\cdot\vec n=0; the intersection is found by substituting xx, yy, zz in terms of tt into (P)(P).

Steps:

  1. Read the direction vector from the coefficients of tt.
  2. Compute u⃗⋅n⃗\vec u\cdot\vec n and solve the equation in tt.
Exercise 5.

What you need: cos⁡φ=∣u⃗1⋅u⃗2∣∣u⃗1∣⋅∣u⃗2∣\cos\varphi=\dfrac{|\vec u_1\cdot\vec u_2|}{|\vec u_1|\cdot|\vec u_2|}.

Steps:

  1. u⃗1=(1,1,0)\vec u_1=(1, 1, 0) and u⃗2=(0,1,−1)\vec u_2=(0, 1, -1).
  2. Substitute into the formula.
Exercise 6.

What you need: the normal vector n⃗=[AB→,AC→]\vec n=[\overrightarrow{AB}, \overrightarrow{AC}].

Steps:

  1. AB→=(1,1,−1)\overrightarrow{AB}=(1, 1, -1) and AC→=(−1,2,2)\overrightarrow{AC}=(-1, 2, 2); compute the vector product.
  2. Write the equation of (ABC)(ABC), then find the distance.
Exercise 7.

What you need: AB=(xB−xA)2+(yB−yA)2+(zB−zA)2AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2+(z_B-z_A)^2}.

Steps:

  1. Find AB→\overrightarrow{AB}.
  2. Find its length.
Exercise 8.

What you need: the drone reaches the boundary of the zone when the coordinates of MM satisfy x+2y+2z=30x+2y+2z=30.

Steps:

  1. Substitute the coordinates of MM into x+2y+2zx+2y+2z.
  2. Solve the equation for tt.
Exercise 9.

What you need: dd takes n⃗P\vec n_P as its direction vector; H=d∩(P)H=d\cap(P).

Steps:

  1. Write d ⁣:x=3+td\colon x=3+t, y=1+2ty=1+2t, z=−2−2tz=-2-2t.
  2. Substitute into (P)(P) to find tt, hence HH; then find AHAH.
Exercise 10.

What you need: the radius is R=d(I,(P))R=d(I, (P)); the point of contact is the orthogonal projection of II on (P)(P).

Steps:

  1. Find RR.
  2. Write the line through II perpendicular to (P)(P) and find where it meets (P)(P).

Self-check

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