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LemonmathSelf-study sheet
Grade 12 · Lesson 2.1

Vectors and their operations in space

Name: Date: Time spent: min

Goals

Remember

Exercises

Exercise 1

Let ABCD.A′B′C′D′ABCD.A'B'C'D' be a parallelepiped. Simplify

a) AB→+BC→+CD′→\overrightarrow{AB}+\overrightarrow{BC}+\overrightarrow{CD'}; b) AB→+A′D′→+CC′→\overrightarrow{AB}+\overrightarrow{A'D'}+\overrightarrow{CC'}.

Exercise 2

Let ABCDABCD be a tetrahedron. Simplify AB→−AC→+DC→−DB→\overrightarrow{AB}-\overrightarrow{AC}+\overrightarrow{DC}-\overrightarrow{DB}.

Exercise 3

Let ABCD.A′B′C′D′ABCD.A'B'C'D' be a cube with edge 33. Find AB→⋅AC→\overrightarrow{AB}\cdot\overrightarrow{AC}, AB→⋅A′C′→\overrightarrow{AB}\cdot\overrightarrow{A'C'} and AA′→⋅BD→\overrightarrow{AA'}\cdot\overrightarrow{BD}.

Exercise 4

Let ABCDABCD be a regular tetrahedron with edge 22 (all edges equal 22, all faces are equilateral triangles). Find AB→⋅AC→\overrightarrow{AB}\cdot\overrightarrow{AC}, then prove that AB⊥CDAB\perp CD.

Exercise 5

Three people pull a crate standing in the corner of a warehouse. The three pulling forces are pairwise perpendicular (along the two walls and straight up), with magnitudes 3030 N, 4040 N and 120120 N. Find the magnitude of the resultant force.

Exercise 6

Let ABCD.A′B′C′D′ABCD.A'B'C'D' be a cube with edge 11. Is each claim true or false?

a) AB→+AD→+AA′→=AC′→\overrightarrow{AB}+\overrightarrow{AD}+\overrightarrow{AA'}=\overrightarrow{AC'}.

b) AC′=3AC'=\sqrt3.

c) AB→⋅CD′→=1\overrightarrow{AB}\cdot\overrightarrow{CD'}=1.

d) The angle between the vectors AC→\overrightarrow{AC} and B′D′→\overrightarrow{B'D'} is 90∘90^\circ.

Exercise 7

A storeroom is a cuboid ABCD.A′B′C′D′ABCD.A'B'C'D' with AB=4AB=4 m, AD=3AD=3 m, AA′=4AA'=4 m. Find the angle between the vectors AC′→\overrightarrow{AC'} and AC→\overrightarrow{AC} (in degrees, rounded to the nearest whole number).

Exercise 8

(Revisiting Multiplying a vector by a number.) Let ABCDABCD be a tetrahedron and GG the centroid of triangle BCDBCD. Prove that AB→+AC→+AD→=3AG→\overrightarrow{AB}+\overrightarrow{AC}+\overrightarrow{AD}=3\overrightarrow{AG}.

Exercise 9 Challenge

a) Prove that for any four points AA, BB, CC, DD: AB→⋅CD→+AC→⋅DB→+AD→⋅BC→=0.\overrightarrow{AB}\cdot\overrightarrow{CD}+\overrightarrow{AC}\cdot\overrightarrow{DB}+\overrightarrow{AD}\cdot\overrightarrow{BC}=0. b) A tetrahedron ABCDABCD has AB⊥CDAB\perp CD and AC⊥BDAC\perp BD. Prove that AD⊥BCAD\perp BC.

Mini test

15 minutes, without looking back at the lesson. Part I: circle one letter; Part II: write T or F for each statement; Part III: write the answer in the box.

Part I. Multiple choice

Question 1. Let ABCD.A′B′C′D′ABCD.A'B'C'D' be a parallelepiped. The vector AB→+AD→−CC′→\overrightarrow{AB}+\overrightarrow{AD}-\overrightarrow{CC'} equals
A. AC→\overrightarrow{AC}.B. AC′→\overrightarrow{AC'}.C. CA′→\overrightarrow{CA'}.D. A′C→\overrightarrow{A'C}.
Question 2. Let ABCDABCD be a tetrahedron, and MM, NN the midpoints of ABAB and CDCD. Then AC→+BD→\overrightarrow{AC}+\overrightarrow{BD} equals
A. 2MN→2\overrightarrow{MN}.B. 12MN→\dfrac12\overrightarrow{MN}.C. MN→\overrightarrow{MN}.D. −2MN→-2\overrightarrow{MN}.
Question 3. Let ABCD.A′B′C′D′ABCD.A'B'C'D' be a cube. The angle between the vectors AB→\overrightarrow{AB} and C′A′→\overrightarrow{C'A'} is
A. 45∘45^\circ.B. 135∘135^\circ.C. 90∘90^\circ.D. 60∘60^\circ.
Question 4. Let ABCDABCD be a regular tetrahedron with edge aa. The scalar product AB→⋅BC→\overrightarrow{AB}\cdot\overrightarrow{BC} is
A. a232\dfrac{a^2\sqrt3}{2}.B. a22\dfrac{a^2}{2}.C. −a22-\dfrac{a^2}{2}.D. 00.

Part II. True or false

Question 1. The cuboid ABCD.A′B′C′D′ABCD.A'B'C'D' has AB=2AB=2, AD=3AD=3, AA′=6AA'=6.
a) AB→⋅AA′→=0\overrightarrow{AB}\cdot\overrightarrow{AA'}=0.T / F
b) AC′=7AC'=7.T / F
c) AC′→⋅AB→=2\overrightarrow{AC'}\cdot\overrightarrow{AB}=2.T / F
d) The angle between the vectors AC′→\overrightarrow{AC'} and AA′→\overrightarrow{AA'} is greater than 35∘35^\circ. T / F

Part III. Short answer

Question 1. Let ABCD.A′B′C′D′ABCD.A'B'C'D' be a cube with edge 22. Find AC′→⋅BD′→\overrightarrow{AC'}\cdot\overrightarrow{BD'}.
Question 2. A drone takes off from a point AA, flies 3030 m east, then 4040 m north, then straight up 2020 m. How far is the drone's final position from AA, in metres? Give your answer to 1 decimal place.

Score: ........ / 10

Hints (only when stuck)

Exercise 1.

What you need: the triangle rule; the parallelepiped rule; parallel edges in the same direction give equal vectors.

Steps:

  1. a) The vectors already join tip to tail.
  2. b) Replace A′D′→=AD→\overrightarrow{A'D'}=\overrightarrow{AD} and CC′→=AA′→\overrightarrow{CC'}=\overrightarrow{AA'}.
Exercise 2.

What you need: the subtraction rule OX→−OY→=YX→\overrightarrow{OX}-\overrightarrow{OY}=\overrightarrow{YX}.

Steps:

  1. Combine AB→−AC→\overrightarrow{AB}-\overrightarrow{AC}.
  2. Combine DC→−DB→\overrightarrow{DC}-\overrightarrow{DB}.
Exercise 3.

What you need: a⃗⋅b⃗=∣a⃗∣∣b⃗∣cos⁡(a⃗,b⃗)\vec{a}\cdot\vec{b}=|\vec{a}||\vec{b}|\cos(\vec{a}, \vec{b}); draw both vectors from a common point before measuring the angle.

Steps:

  1. AC=32AC=3\sqrt2 and ∠BAC=45∘\angle BAC=45^\circ.
  2. A′C′→=AC→\overrightarrow{A'C'}=\overrightarrow{AC}.
  3. AA′AA' is perpendicular to the base, so it is perpendicular to BDBD.
Exercise 4.

What you need: the angles of an equilateral triangle are 60∘60^\circ; CD→=AD→−AC→\overrightarrow{CD}=\overrightarrow{AD}-\overrightarrow{AC}.

Steps:

  1. Find AB→⋅AC→\overrightarrow{AB}\cdot\overrightarrow{AC} and AB→⋅AD→\overrightarrow{AB}\cdot\overrightarrow{AD}.
  2. Find AB→⋅CD→\overrightarrow{AB}\cdot\overrightarrow{CD} by replacing CD→\overrightarrow{CD}.
Exercise 5.

What you need: the resultant is the sum of the three force vectors; for three pairwise perpendicular vectors, ∣a⃗+b⃗+c⃗∣2=∣a⃗∣2+∣b⃗∣2+∣c⃗∣2|\vec{a}+\vec{b}+\vec{c}|^2=|\vec{a}|^2+|\vec{b}|^2+|\vec{c}|^2.

Steps:

  1. Square the sum of the three forces.
  2. The scalar products of different forces are 00.
Exercise 6.

What you need: the parallelepiped rule; the three edges at AA are pairwise perpendicular with length 11; write every vector in terms of AB→\overrightarrow{AB}, AD→\overrightarrow{AD}, AA′→\overrightarrow{AA'}.

Steps:

  1. b) Square AC′→\overrightarrow{AC'}.
  2. c) CD′→=CD→+DD′→=−AB→+AA′→\overrightarrow{CD'}=\overrightarrow{CD}+\overrightarrow{DD'}=-\overrightarrow{AB}+\overrightarrow{AA'}.
  3. d) B′D′→=BD→\overrightarrow{B'D'}=\overrightarrow{BD}; the diagonals of a square are perpendicular.
Exercise 7.

What you need: cos⁡(a⃗,b⃗)=a⃗⋅b⃗∣a⃗∣∣b⃗∣\cos(\vec{a}, \vec{b})=\dfrac{\vec{a}\cdot\vec{b}}{|\vec{a}||\vec{b}|}; the parallelepiped rule.

Steps:

  1. Write AC→=AB→+AD→\overrightarrow{AC}=\overrightarrow{AB}+\overrightarrow{AD} and AC′→=AB→+AD→+AA′→\overrightarrow{AC'}=\overrightarrow{AB}+\overrightarrow{AD}+\overrightarrow{AA'}.
  2. Find the scalar product and the two lengths.
Exercise 8.

What you need: GG is the centroid of triangle BCDBCD   ⟺  \iff GB→+GC→+GD→=0⃗\overrightarrow{GB}+\overrightarrow{GC}+\overrightarrow{GD}=\vec{0} (grade 10).

Steps:

  1. Insert the point GG: AB→=AG→+GB→\overrightarrow{AB}=\overrightarrow{AG}+\overrightarrow{GB}, and so on.
  2. Add the three equalities.
Exercise 9.

What you need: insert the point AA: CD→=AD→−AC→\overrightarrow{CD}=\overrightarrow{AD}-\overrightarrow{AC}; the scalar product distributes over addition.

Steps:

  1. Put b⃗=AB→\vec{b}=\overrightarrow{AB}, c⃗=AC→\vec{c}=\overrightarrow{AC}, d⃗=AD→\vec{d}=\overrightarrow{AD} and write every vector in terms of them.
  2. Expand; the terms cancel in pairs.
  3. b) The first two products are 00.

Self-check

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