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LemonmathSelf-study sheet
Grade 9 · Lesson 6.4

Solving word problems by forming equations

Name: Date: Time spent: min

Goals

Remember

Exercises

Exercise 1

Find two consecutive even natural numbers whose product is 224224.

Exercise 2

A right-angled triangle has hypotenuse 1313 cm, and its two shorter sides differ by 77 cm. Find the lengths of the two shorter sides.

Exercise 3

According to plan, a production team must make 600600 products, the same number each day. Thanks to a technical improvement, the team makes 1010 more products each day and finishes 22 days ahead of plan. How many products per day did the plan require?

Exercise 4

A motorboat travels 3535 km downstream and then 3535 km upstream, taking 66 hours in total (not counting stops). The current flows at 22 km/h. Find the speed of the boat in still water.

Exercise 5

Suppose the price of a mobile phone falls from 55 million dong to 4.054.05 million dong after two reductions, each by the same percentage of the price just before it. By what percentage is the price reduced each time?

Exercise 6

A rectangular photo measuring 1212 cm ×\times 88 cm is put in a frame with a border of constant width. The total area of the frame and photo is 140140 cm². Find the width of the border. (Revise finding roots mentally.)

Exercise 7

(2.0 marks)

a) Solve the equation x2−2x−35=0x^2-2x-35=0.

b) Solve the following problem by forming an equation: A group of students hires a coach for a trip for 4.24.2 million dong, shared equally. On the day of the trip, 22 more students join, so each student pays 1010 thousand dong less than expected. How many students were in the group at first?

c) How much does each student actually pay?

Exercise 8 Challenge

Suppose a cinema sells 300300 tickets a day at a price of 6060 thousand dong. A survey shows that for every 55 thousand dong cut from the price, it sells 5050 more tickets a day. The cinema wants a daily revenue of 2020 million dong and chooses the option that sells more tickets. What is the new ticket price?

Mini test

15 minutes, without looking back at the lesson. Part I: circle one letter; Part II: write T or F for each statement; Part III: write the answer in the box.

Part I. Multiple choice

Question 1. The product of two consecutive natural numbers is 110110. If the smaller number is xx, which equation is correct?
A. x(x+1)=110x(x+1)=110.B. x+(x+1)=110x+(x+1)=110.C. x2+1=110x^2+1=110.D. 2x+1=1102x+1=110.
Question 2. A car travels 9090 km at a speed of xx (km/h). If it went 1515 km/h faster, it would arrive 11 hour earlier. Which equation is correct?
A. 90x−90x+15=1\dfrac{90}{x}-\dfrac{90}{x+15}=1.B. 90x+15−90x=1\dfrac{90}{x+15}-\dfrac{90}{x}=1.C. 90x+90x+15=1\dfrac{90}{x}+\dfrac{90}{x+15}=1.D. 90x−90(x+15)=190x-90(x+15)=1.
Question 3. In a problem where the unknown xx is a width (m), we get the equation x2+3x−70=0x^2+3x-70=0 with roots 77 and −10-10. The width is
A. 77 m.B. −10-10 m.C. 77 m or 1010 m.D. 1010 m.
Question 4. The price of a product rises from 200200 thousand dong to 242242 thousand dong after two increases, each by r%r\% of the previous price. The value of rr is
A. 1010.B. 2121.C. 10.510.5.D. 1111.

Part II. True or false

Question 1. A rectangular garden is 44 m longer than it is wide and has area 9696 m². Let the width be xx (m), x>0x>0. Decide whether each statement is true or false.
a) The length of the garden is x+4x+4 (m).T / F
b) We have the equation x2+4x−96=0x^2+4x-96=0.T / F
c) The width of the garden is 1212 m.T / F
d) The perimeter of the garden is 4040 m. T / F

Part III. Short answer

Question 1. The product of two consecutive even natural numbers is 288288. Find the larger number.
Question 2. Suppose the population of a ward grows from 20 00020\,000 to 20 80820\,808 people in 22 years, at the same rate of r%r\% each year. Find rr.

Score: ........ / 10

Hints (only when stuck)

Exercise 1.

What you need: two consecutive even numbers differ by 22.

Steps:

  1. Let the smaller number be xx and the larger x+2x+2.
  2. Solve x(x+2)=224x(x+2)=224.
Exercise 2.

What you need: Pythagoras' theorem.

Steps:

  1. Let the shortest side be xx (cm), x>0x>0; the other is x+7x+7.
  2. Solve x2+(x+7)2=169x^2+(x+7)^2=169.
Exercise 3.

What you need: number of days=total number of productsrate\text{number of days}=\dfrac{\text{total number of products}}{\text{rate}}.

Steps:

  1. Let the planned rate be xx (products per day), x∈N∗x\in\mathbb{N}^*.
  2. Form the equation 600x−600x+10=2\dfrac{600}{x}-\dfrac{600}{x+10}=2.
Exercise 4.

What you need: speed downstream =x+2=x+2, speed upstream =x−2=x-2.

Steps:

  1. Let the speed in still water be xx (km/h), x>2x>2.
  2. Form the equation 35x+2+35x−2=6\dfrac{35}{x+2}+\dfrac{35}{x-2}=6 and solve it.
Exercise 5.

What you need: each reduction by rr multiplies the price by 1−r1-r.

Steps:

  1. Form the equation 5(1−r)2=4.055(1-r)^2=4.05 with 0<r<10<r<1.
  2. Solve it as X2=kX^2=k.
Exercise 6.

What you need: the whole frame is a rectangle (12+2x)×(8+2x)(12+2x)\times(8+2x); find the roots mentally when a+b+c=0a+b+c=0.

Steps:

  1. Let the width of the border be xx (cm), x>0x>0.
  2. Form the equation, simplify it, then find the roots mentally.
Exercise 7.

What you need: the reduced discriminant; the amount per student =total costnumber of students=\dfrac{\text{total cost}}{\text{number of students}}.

Steps:

  1. a) Work out Δ′\Delta'.
  2. b) Work in thousands of dong: 4.24.2 million =4200=4200 thousand. Let the original number of students be xx and form 4200x−4200x+2=10\dfrac{4200}{x}-\dfrac{4200}{x+2}=10.
  3. c) Divide the total cost by x+2x+2.
Exercise 8.

What you need: revenue == price ×\times number of tickets; the number of tickets and the price depend on each other.

Steps:

  1. Let the number of 55 thousand dong cuts be xx (x∈Nx\in\mathbb{N}, x<12x<12).
  2. The price is 60−5x60-5x and the number of tickets is 300+50x300+50x; form the equation with revenue 20 00020\,000 thousand dong.
  3. Choose the root that gives more tickets.

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