Two students each get 8 true/false statements right in Part II. Hà gets all 4 statements right in two questions and none in the other two. Nam gets 2 statements right in each of the four questions. Who scores more?
The answer lies in how Part II is marked, and it directly affects how you should work. This lesson describes the format of the specimen papers published by the Ministry of Education and Training from 2025, and the habits that stop you losing marks needlessly. The Ministry may adjust the format or the marking from year to year, so check its official announcement for your exam year.
Format and marking
The paper has three parts, lasts 90 minutes, and is marked out of 10.
Part
Question type
Questions
Mark each
Total
I
Multiple choice (A, B, C, D)
12
0.25
3
II
True/false, each with 4 statements a), b), c), d)
4
up to 1
4
III
Short answer
6
0.5
3
The mark rises steeply at the last statement: going from 3 to 4 correct doubles the mark. So every statement is worth checking carefully.
Back to the opening question: Hà scores 1+1=2, while Nam scores 4⋅0.25=1. The same 8 correct statements, but Hà scores twice as much.
Part I: multiple choice
Each question has exactly one correct option and wrong answers lose nothing. So never leave a question blank. Part I questions are usually short and test one formula or one step.
Three quick methods:
Solve directly, then match with the options.
Work backwards: put each option into the condition of the question (for example, differentiate an option to check an antiderivative).
Eliminate: wrong options usually come from a familiar mistake (wrong sign, missing coefficient, wrong formula). Spotting the mistake lets you rule them out quickly.
Part II: true or false
Each question gives a common setting (a function, a figure, a data table) followed by four statements. Later statements are usually harder.
Part III: short answers and the 4 boxes
Each answer is one number, written on the sheet in 4 boxes. The minus sign and the decimal comma each take a box (the Vietnamese sheet uses a comma, not a point, as the decimal separator).
Writing the answer −0.5 in 4 boxes
For example, 47=1.75 is written 1,75 (all 4 boxes); −32 to 1 decimal place is −0.7 (all 4 boxes).
Time plan and checking
90 minutes for 22 questions is tight. A suggested plan:
Task
Suggested time
Part I (12 questions)
about 20–25 minutes
Part II (4 questions)
about 25–30 minutes
Part III (6 questions)
about 25–30 minutes
Checking, filling in the sheet
about 5–10 minutes
Work in order of difficulty, not necessarily in question order: on a first pass do every question you are sure of, mark the hard ones, then come back. Do not spend more than 5 minutes on one Part I question.
Use your scientific calculator to check: evaluate a function at given points, compute definite integrals, solve quadratic and cubic equations. The calculator catches slips, but you still need reasoning to know what to compute.
Key terms
Exercises
Each exercise comes with what you need and some steps to start. Try it yourself first, then open the solution.
Exercise 1 Multiple choice
In one true/false question you judge 3 statements correctly. What mark do you get for that question?
A. 0.5.
B. 0.75.
C. 0.25.
D. 1.
What you need and how to start
What you need: the Part II scale: 1, 2, 3, 4 correct statements give 0.1, 0.25, 0.5, 1.
Steps:
Read off the mark for 3 correct statements.
Show solution
By the scale, 3 correct statements give 0.5. Option B is the mistake 3⋅0.25.
Answer. A.
Exercise 2 Written answer
Bình gets 9 questions right in Part I; in Part II, 4, 4, 2, 1 statements right; in Part III, 3 questions right. Find Bình's mark.
What you need and how to start
What you need: Part I 0.25 per question; Part II by the scale; Part III 0.5 per question.
Steps:
Work out each part.
Add the three parts.
Show solution
Part I: 9⋅0.25=2.25. Part II: 1+1+0.25+0.1=2.35. Part III: 3⋅0.5=1.5.
Answer.2.25+2.35+1.5=6.1.
Exercise 3 Short answer
A short-answer question asks for 1 decimal place, and the exact result is −32. What do you write in the 4 boxes? Why does the question not ask for 2 decimal places?
What you need and how to start
What you need: the minus sign and the comma each take a box.
Steps:
Work out −32≈−0.667 and round to 1 decimal place.
Count the characters if rounded to 2 decimal places.
Show solution
−32≈−0.667, which to 1 decimal place is −0.7: four characters "−", "0", ",", "7". To 2 decimal places it would be −0.67, which needs 5 boxes and cannot be written.
Answer.−0.7.
Exercise 4 Multiple choice
The horizontal asymptote of the graph of y=x−12x+1 is
A. y=2.
B. x=1.
C. y=−1.
D. x=2.
What you need and how to start
What you need: a horizontal asymptote has the form y=b with b=x→±∞limy.
Steps:
Rule out the options of the form x=… straight away.
Find the limit as x→+∞.
Show solution
Options B and D are vertical lines, so they are ruled out. x→±∞limx−12x+1=2. Option C takes the ratio of the constant terms −11.
Answer. A.
Exercise 5 True/False
Given ∫02f(x)dx=3 and ∫02g(x)dx=−1.
a) ∫02[f(x)+g(x)]dx=2.
b) ∫022f(x)dx=6.
c) ∫20g(x)dx=1.
d) ∫02f(x)g(x)dx=−3.
What you need and how to start
What you need: the integral of a sum is the sum of the integrals; a constant factor comes outside; swapping the limits changes the sign. There is no rule for the integral of a product.
Steps:
Judge each statement with exactly one property.
Show solution
a) True: 3+(−1)=2.
b) True: 2⋅3=6.
c) True: swapping the limits changes the sign, −(−1)=1.
d) False: the integral of a product is not the product of the integrals. For instance f(x)=23 and g(x)=−x+21 satisfy the conditions, but ∫02f(x)g(x)dx=−23.
Answer. a) True; b) True; c) True; d) False.
Exercise 6 Short answer
A car moves with velocity v(t)=3t2+2 (m/s), with t in seconds. Find the distance it travels in the first 3 seconds, in metres.
What you need and how to start
What you need: the distance is the integral of the velocity when v(t)≥0.
Steps:
Write s=∫03(3t2+2)dt.
Use the antiderivative t3+2t.
Show solution
s=∫03(3t2+2)dt=[t3+2t]03=27+6=33.
Answer.33.
Exercise 7 Short answer
Two events A, B have P(A)=0.4, P(B∣A)=0.3 and P(B∣A)=0.5. Find P(B).
What you need and how to start
What you need: the law of total probability P(B)=P(A)P(B∣A)+P(A)P(B∣A).
Steps:
Find P(A)=1−0.4.
Substitute into the formula.
Show solution
P(B)=0.4⋅0.3+0.6⋅0.5=0.12+0.3=0.42.
Answer.0.42.
Exercise 8 Challenge
Minh plans the 90-minute paper: the last 5 minutes for checking, 2 minutes for each Part I question and 5 minutes for each Part III question. The remaining time is shared equally among the 4 Part II questions. How many minutes does each Part II question get?
What you need and how to start
What you need: Part I has 12 questions and Part III has 6.
Steps:
Work out the time for Parts I and III.
Subtract everything from 90 and divide by 4.
Show solution
Part I: 12⋅2=24 minutes; Part III: 6⋅5=30 minutes. That leaves 90−5−24−30=31 minutes for Part II, so 431=7.75 minutes per question.
Answer.7.75 minutes (about 7 minutes 45 seconds).
Mini test
Mini test
Marked like the Vietnamese graduation exam: Part I 0.25 points per question; Part II up to 1 point per question (1, 2, 3, 4 correct statements give 0.1, 0.25, 0.5, 1 point); Part III 0.5 points per question.
Part I. Multiple choice
Question 1. The greatest possible mark for Part II is
Answer: A.
Part II has 4 questions worth up to 1 mark each. Option B is the maximum for one question; option C is the total for Part I or Part III.
Question 2. The minimum value of y=x2−4x+5 on [0,3] is
Answer: A.
y′=2x−4=0⟺x=2∈(0,3). Compare y(0)=5, y(2)=1, y(3)=2. Option B is y(3), from comparing only the endpoints.
Question 3. The result of a short-answer question is 37, to be given to 1 decimal place. You write
Answer: A.
37≈2.333; the second decimal digit is 3<5, so we round down to 2.3. C rounds to the wrong place, D to the nearest whole number.
Question 4. The integral ∫013x2dx equals
Answer: A.
[x3]01=1. Option C is the derivative 6x at x=1; option D computes F(0)−F(1).
Part II. True or false
Question 1. In Part II, a student judges 4, 3, 1, 0 statements correctly in the four questions.
a) The student gets 1 mark for the first question.
b) The student gets 0.75 for the second question.
c) The student gets 0.1 for the third question.
d) The student's total for Part II is 1.6.
Answer: a) True; b) False; c) True; d) True.
a) True: 4 correct statements give 1 mark. b) False: 3 correct statements give 0.5. c) True. d) True: 1+0.5+0.1+0=1.6.
Part III. Short answer
Question 1. A student gets 11 questions right in Part I, exactly 3 statements right in every Part II question, and 3 questions right in Part III. What is the student's mark?
Answer: 6.25.
Part I: 11⋅0.25=2.75; Part II: 4⋅0.5=2; Part III: 3⋅0.5=1.5. Total 6.25.
Question 2. Find ∫01exdx. Give your answer to 2 decimal places.
Answer: 1.72.
[ex]01=e−1≈1.718, which rounds to 1.72.
Show answers and explanations
Part I, question 1: A. Part II has 4 questions worth up to 1 mark each. Option B is the maximum for one question; option C is the total for Part I or Part III.
Part I, question 2: A. y′=2x−4=0⟺x=2∈(0,3). Compare y(0)=5, y(2)=1, y(3)=2. Option B is y(3), from comparing only the endpoints.
Part I, question 3: A. 37≈2.333; the second decimal digit is 3<5, so we round down to 2.3. C rounds to the wrong place, D to the nearest whole number.
Part I, question 4: A. [x3]01=1. Option C is the derivative 6x at x=1; option D computes F(0)−F(1).
Part II, question 1: a) True; b) False; c) True; d) True. a) True: 4 correct statements give 1 mark. b) False: 3 correct statements give 0.5. c) True. d) True: 1+0.5+0.1+0=1.6.
Part III, question 1: 6.25. Part I: 11⋅0.25=2.75; Part II: 4⋅0.5=2; Part III: 3⋅0.5=1.5. Total 6.25.
Part III, question 2: 1.72. [ex]01=e−1≈1.718, which rounds to 1.72.